[arin-ppml] how to get a v6 /32 of v4 address space

[Cynthia Revström]

I have no clue what your point is but an IPv6 /32 is 2^96 IP addresses. The
total possible IPv4 address space is 2^32.

So your point doesn't make much sense to me.

- Cynthia

On Sun, May 19, 2019 at 5:54 AM william manning <chinese.apricot at gmail.com>
wrote:

> ok, so you don't like the "use 127.0.0.0/8" proposal. fine.
> RFC 1918 space is too small.  fine.
> IPv6 is too hard. fine.
>
> Shortly after discussions started on RF 1918, I proposed the following:
>
> Since NAT exists, direct peering on a global scale will be fairly
> restrictive, one should consider inverting RFC 1918.  Use those addresses
> strictly and only for global interconnection/peering.
>
> This would free up all other IPv4 space to sit behind your NAT and usable
> in your enterprise networks.  Thats almost an entire IPv6 /32 of space for
> everyone, without having to migrate to IPv6.
>
> Problem solved.
>
> Your welcome.
>
> /Wm
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