[arin-ppml] how to get a v6 /32 of v4 address space

Cynthia Revström me at cynthia.re
Sun May 19 08:18:43 EDT 2019

I have no clue what your point is but an IPv6 /32 is 2^96 IP addresses. The
total possible IPv4 address space is 2^32.

So your point doesn't make much sense to me.

- Cynthia

On Sun, May 19, 2019 at 5:54 AM william manning <chinese.apricot at gmail.com>

> ok, so you don't like the "use" proposal. fine.
> RFC 1918 space is too small.  fine.
> IPv6 is too hard. fine.
> Shortly after discussions started on RF 1918, I proposed the following:
> Since NAT exists, direct peering on a global scale will be fairly
> restrictive, one should consider inverting RFC 1918.  Use those addresses
> strictly and only for global interconnection/peering.
> This would free up all other IPv4 space to sit behind your NAT and usable
> in your enterprise networks.  Thats almost an entire IPv6 /32 of space for
> everyone, without having to migrate to IPv6.
> Problem solved.
> Your welcome.
> /Wm
> _______________________________________________
> You are receiving this message because you are subscribed to
> the ARIN Public Policy Mailing List (ARIN-PPML at arin.net).
> Unsubscribe or manage your mailing list subscription at:
> https://lists.arin.net/mailman/listinfo/arin-ppml
> Please contact info at arin.net if you experience any issues.
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <https://lists.arin.net/pipermail/arin-ppml/attachments/20190519/87d272ba/attachment-0002.html>

More information about the ARIN-PPML mailing list