[arin-ppml] how to get a v6 /32 of v4 address space
me at cynthia.re
Sun May 19 08:18:43 EDT 2019
I have no clue what your point is but an IPv6 /32 is 2^96 IP addresses. The
total possible IPv4 address space is 2^32.
So your point doesn't make much sense to me.
On Sun, May 19, 2019 at 5:54 AM william manning <chinese.apricot at gmail.com>
> ok, so you don't like the "use 127.0.0.0/8" proposal. fine.
> RFC 1918 space is too small. fine.
> IPv6 is too hard. fine.
> Shortly after discussions started on RF 1918, I proposed the following:
> Since NAT exists, direct peering on a global scale will be fairly
> restrictive, one should consider inverting RFC 1918. Use those addresses
> strictly and only for global interconnection/peering.
> This would free up all other IPv4 space to sit behind your NAT and usable
> in your enterprise networks. Thats almost an entire IPv6 /32 of space for
> everyone, without having to migrate to IPv6.
> Problem solved.
> Your welcome.
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